This content originally appeared on DEV Community and was authored by Rakesh Reddy Peddamallu
Lets quickly go into the solution for the unique email addresses problem
we can see every email in localName + @ + domainName this form
let localName = email.split('@')[0] ?? '';
const domainName = email.split('@')[1];
And the question tells if localName has + sign in it we need to ignore the rest of the characters after it , example "m.y+name@email.com" is equal to "m.y@email.com"
if (localName.includes('+')) {
localName = localName.split('+')?.[0];
}
Also the question tells us that if we have . in email then it is considered as forwardable to the email , after replacing . (dot) with '' empty character
if (localName.includes('.') || domainName.includes('.')) {
isForwardable = true;
localName = localName.replace(/\./g, '');
}
if (isForwardable) {
return localName + '@' + domainName; //returning email
} else {
return ''; //returning empty string if not forwardible
}
Complete code
/**
* @param {string[]} emails
* @return {number}
*/
const convertEmail = email => {
let localName = email.split('@')[0] ?? '';
const domainName = email.split('@')[1];
let isForwardable = false;
if (localName.includes('+')) {
localName = localName.split('+')?.[0];
}
if (localName.includes('.') || domainName.includes('.')) {
isForwardable = true;
localName = localName.replace(/\./g, '');
}
if (isForwardable) {
return localName + '@' + domainName;
} else {
return '';
}
};
var numUniqueEmails = function(emails) {
let uniqueEmails = new Set();
emails.forEach(email => {
const convertedEmail = convertEmail(email);
if (convertedEmail !== '') {
uniqueEmails.add(convertedEmail);
}
});
return uniqueEmails.size;
};
Please do follow the series if you are struggling with leetcode questions 😇
This content originally appeared on DEV Community and was authored by Rakesh Reddy Peddamallu
Rakesh Reddy Peddamallu | Sciencx (2024-06-24T03:51:41+00:00) Leetcode – 929. Unique Email Addresses. Retrieved from https://www.scien.cx/2024/06/24/leetcode-929-unique-email-addresses/
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