I did it…. Fish Eye… Call Me Kinlan The Chuffed!!!

It wasn’t too hard…. I did take a peak at the code behind the fish eye that Jason Waltman describes. I did this purely because the code I implemented seemed to match the pseduo code that was written but my results were not quite correct. I looked at the code, converted it to c# implemented it as a filter in the Tiger Image Processing Library (Tiger Imaging) for C# here and it worked pretty much the first time it was tan.


This content originally appeared on Modern Web Development with Chrome and was authored by Paul Kinlan

<p>It wasn't too hard.... I did take a peak at the code behind the <a href="http://www.jasonwaltman.com/thesis/filter-fisheye.html/tag" rel="tag" target="_blank">fish eye</a> that <a href="http://www.jasonwaltman.com/" target="_blank"><strong><span style="COLOR: #4386ce;">Jason Waltman</span></strong></a> describes. I did this purely because the code I implemented seemed to match the pseduo code that was written but my results were not quite correct. I looked at the code, converted it to c# implemented it as a filter in the Tiger Image Processing Library (Tiger Imaging) for C# <a href="http://www.thecodeproject.com/cs/media/Image_Processing_Lab.asp" target="_blank"><strong><span style="COLOR: #4386ce;">here</span></strong></a> and it worked pretty much the first time it was tan.<p />I understand a bit more about polar co-ordinates now as well :)<p />Basically we have are our normal Cartesian Co-ordinates (x,y) which are used on our screens as pixel locations ((0,0) is the top left, (10,10) is 10 pixels in from the top left etc). Polar co-ordinates are co-ordinates that are specified in Angles and units from the center of a Circle .... I think!<p />So a Polar Co-ordinate (angle = 45, radius = 20) would mean that the point we want is 45 degrees from North and 20 units out from the centre.<p />This is useful in the Fish Eye Effect which needs to work out what pixels will be in the fish eye region.<p />The Fish eye effect has two basic stages<ul></p> <li>Work out which pixel should be fish eyed</li> <li>If a pixel needs to be fish eyed, work out where the pixel should be placed based on where it is in the fish eye's view.</li> </ul>Hmm.... Don't know if I made too much sense there, but I will comment the code a bit more and then post it as a link.


This content originally appeared on Modern Web Development with Chrome and was authored by Paul Kinlan


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