This content originally appeared on DEV Community and was authored by SuperTokens
For redux to work correctly, the state must be immutable. This means that whenever we update the redux state, we have to create a copy of the whole state and set values to fields we want to change. In code, this usually looks like:
let newState = {
...oldState,
field1: {
...oldState.field1,
field2: "someNewValue"
},
}
In the code above, we are modifying the oldState’s field2 value by creating a new state and setting a new value to field2. The value and reference of oldState remains the same.
Before we get into why we must change redux state in this way, we should know the difference between “value” and “reference”
Difference between value and reference
The value of a variable is the “semantic” meaning of what that variable holds. For example, in the example code below, the semantics of what is held by var1 and var2 are the same, therefore we can say that their values are the same. However, var3’s value is different since the “semantics” of what it’s holding is different.
let var1 = { name: "John", age: 20}
let var2 = { name: "John", age: 20}
let var3 = { name: "May", age: 30}
When we talk about reference, we are referring (pun intended!) to the memory address of where something is stored. So in the above example, the memory address of the object referenced by var1, is different from the memory address of the object referenced by var2. In other words, var1 points to a different memory address than var2. Therefore, their references are different, even though their values are the same!
The only way two variables can have the same reference is when they are both pointing to the same memory address. So in the code below, var4 and var5 have the same reference:
let var4 = { name: "Jeremy", age: 50}
let var5 = var4
If we do var5.name = “Mary”, then the value of var4.name will also be “Mary”.
Based on this understanding, we can conclude:
- If the value of two variables are the same, their reference may or may not be the same.
- If the values of two variables are different, then their references must be different.
- If the reference of two variables are the same, their values must be the same.
- If the reference of two variables are different, their values may or may not be the same.
Re rendering of react components
Coming back to redux and react, react will only want to re render a component if the value of the props or state has changed. To know if a value of these have changed, we must do a “deep comparison” - recursively check all the fields inside the state and prop to see if any of them have changed.
Large applications usually have a very deep state structure when using redux - several nested levels (in the count of 100s or even 1000s). Doing a deep comparison here, perhaps several times every second, will slow down the UI. On the other hand, if we do a “shallow comparison” (where we only check if the values of the first level fields have changed), it will be much quicker, but we may miss out on updates - breaking application logic. An example of how we might miss out on updates with shallow comparison is presented below:
let oldState = {
name: "John",
age: 20,
profession: {
title: "Software Engineer",
organization: "SuperTokens.io"
}
}
let newState = oldState
newState.profession.title = "Senior Software Engineer"
// Shallow comparison. upto level one
if (newState !== oldState || oldState.name !== newState.name || oldState.age !== newState.age || oldState.profession !== newState.profession) {
// Update UI
}
Optimising with the immutability rule
The problem of rerendering could be solved if we could somehow just do a shallow reference check, without missing out on updates. This would give us the performance we need and not break the application’s logic.
Based on what we saw in the previous sections, we know that “if the reference of two variables (state variables in this case) are different, their values may or may not be the same.”. What if we change this to “if and only if the reference of two variables (state variables in this case) are different, we should assume that their values are different.”. What happens now?
If the above change is enforced, then to know if a state’s value has changed, we can just do a reference check like oldState === newState (if this is false, then the reference has changed). If the reference has changed, then we can assume that the values must have changed and trigger a render. If not, then we do not rerender.
To enforce this assumption, we must never directly change the fields inside oldState. Instead, we must always create a new copy of oldState (in newState), just like we showed at the start of this article, and make modifications in newState. Since newState is a new object, its reference will always be different than that of oldState. This is known as enforcing immutability of state - exactly what redux enforces its users to do!
Conclusion
Immutability of redux state is necessary since it allows detecting redux state changes in an efficient manner. This implies that whenever we want to modify a redux state, we must create a new copy of it and do modifications to that copy - which then becomes the new redux state.
Written by the Folks at SuperTokens — hope you enjoyed! We are always available on our Discord server. Join us if you have any questions or need any help.
This content originally appeared on DEV Community and was authored by SuperTokens
SuperTokens | Sciencx (2022-01-06T12:18:00+00:00) Why is redux state immutable?. Retrieved from https://www.scien.cx/2022/01/06/why-is-redux-state-immutable/
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